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[CRYPTO] Use standard byte order macros wherever possible

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A lot of crypto code needs to read/write a 32-bit/64-bit words in a
specific gender.  Many of them open code them by reading/writing one
byte at a time.  This patch converts all the applicable usages over
to use the standard byte order macros.

This is based on a previous patch by Denis Vlasenko.

Signed-off-by: Herbert Xu <herbert@gondor.apana.org.au>
This commit is contained in:
Herbert Xu
2005-10-30 21:25:15 +11:00
committed by David S. Miller
parent 2df15fffc6
commit 06ace7a9ba
22 changed files with 284 additions and 440 deletions
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28
crypto/sha1.c
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@@ -21,6 +21,7 @@
#include <linux/mm.h>
#include <linux/crypto.h>
#include <linux/cryptohash.h>
#include <linux/types.h>
#include <asm/scatterlist.h>
#include <asm/byteorder.h>
@@ -72,20 +73,12 @@ static void sha1_update(void *ctx, const u8 *data, unsigned int len)
static void sha1_final(void* ctx, u8 *out)
{
struct sha1_ctx *sctx = ctx;
u32 i, j, index, padlen;
u64 t;
u8 bits[8] = { 0, };
__be32 *dst = (__be32 *)out;
u32 i, index, padlen;
__be64 bits;
static const u8 padding[64] = { 0x80, };
t = sctx->count;
bits[7] = 0xff & t; t>>=8;
bits[6] = 0xff & t; t>>=8;
bits[5] = 0xff & t; t>>=8;
bits[4] = 0xff & t; t>>=8;
bits[3] = 0xff & t; t>>=8;
bits[2] = 0xff & t; t>>=8;
bits[1] = 0xff & t; t>>=8;
bits[0] = 0xff & t;
bits = cpu_to_be64(sctx->count);
/* Pad out to 56 mod 64 */
index = (sctx->count >> 3) & 0x3f;
@@ -93,16 +86,11 @@ static void sha1_final(void* ctx, u8 *out)
sha1_update(sctx, padding, padlen);
/* Append length */
sha1_update(sctx, bits, sizeof bits);
sha1_update(sctx, (const u8 *)&bits, sizeof(bits));
/* Store state in digest */
for (i = j = 0; i < 5; i++, j += 4) {
u32 t2 = sctx->state[i];
out[j+3] = t2 & 0xff; t2>>=8;
out[j+2] = t2 & 0xff; t2>>=8;
out[j+1] = t2 & 0xff; t2>>=8;
out[j ] = t2 & 0xff;
}
for (i = 0; i < 5; i++)
dst[i] = cpu_to_be32(sctx->state[i]);
/* Wipe context */
memset(sctx, 0, sizeof *sctx);