sched: Avoid prev->stime underflow

Dave Hansen reported strange utime/stime values on his system:
https://lkml.org/lkml/2013/4/4/435

This happens because prev->stime value is bigger than rtime
value. Root of the problem are non-monotonic rtime values (i.e.
current rtime is smaller than previous rtime) and that should be
debugged and fixed.

But since problem did not manifest itself before commit
62188451f0 "cputime: Avoid
multiplication overflow on utime scaling", it should be threated
as regression, which we can easily fixed on cputime_adjust()
function.

For now, let's apply this fix, but further work is needed to fix
root of the problem.

Reported-and-tested-by: Dave Hansen <[email protected]>
Cc: <[email protected]> # 3.9+
Signed-off-by: Stanislaw Gruszka <[email protected]>
Cc: Frederic Weisbecker <[email protected]>
Cc: [email protected]
Cc: Linus Torvalds <[email protected]>
Cc: Dave Hansen <[email protected]>
Cc: Peter Zijlstra <[email protected]>
Link: http://lkml.kernel.org/r/[email protected]
Signed-off-by: Ingo Molnar <[email protected]>
This commit is contained in:
Stanislaw Gruszka authored and Ingo Molnar committed 2013-04-30 19:13:05 +02:00
1 parent 772c808a25
commit 68aa8efcd1
1 file changed
+7 -7
+7 -7
View File
@@ -558,7 +558,7 @@ static void cputime_adjust(struct task_cputime *curr,
struct cputime *prev,
cputime_t *ut, cputime_t *st)
{
cputime_t rtime, stime, total;
cputime_t rtime, stime, utime, total;
if (vtime_accounting_enabled()) {
*ut = curr->utime;
@@ -589,13 +589,13 @@ static void cputime_adjust(struct task_cputime *curr,
if (prev->stime + prev->utime >= rtime)
goto out;
if (!rtime) {
stime = 0;
} else if (!total) {
stime = rtime;
} else {
if (total) {
stime = scale_stime((__force u64)stime,
(__force u64)rtime, (__force u64)total);
utime = rtime - stime;
} else {
stime = rtime;
utime = 0;
}
/*
@@ -604,7 +604,7 @@ static void cputime_adjust(struct task_cputime *curr,
* Let's enforce monotonicity.
*/
prev->stime = max(prev->stime, stime);
prev->utime = max(prev->utime, rtime - prev->stime);
prev->utime = max(prev->utime, utime);
out:
*ut = prev->utime;